1=-8v+3(v+2)

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Solution for 1=-8v+3(v+2) equation: 



1=-8v+3(v+2)

We move all terms to the left:

1-(-8v+3(v+2))=0



We calculate terms in parentheses: -(-8v+3(v+2)), so:

-8v+3(v+2)

We multiply parentheses

-8v+3v+6

We add all the numbers together, and all the variables

-5v+6

Back to the equation:

-(-5v+6)



We get rid of parentheses

5v-6+1=0

We add all the numbers together, and all the variables

5v-5=0

We move all terms containing v to the left, all other terms to the right

5v=5

v=5/5

v=1

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