1=1/3(d+3)

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Solution for 1=1/3(d+3) equation: 



1=1/3(d+3)

We move all terms to the left:

1-(1/3(d+3))=0



Domain of the equation: 3(d+3))!=0

d∈R



We multiply all the terms by the denominator


-(1+1*3(d+3))=0



We calculate terms in parentheses: -(1+1*3(d+3)), so:

1+1*3(d+3)

determiningTheFunctionDomain
1*3(d+3)+1

Wy multiply elements

3d(d+1

Back to the equation:

-(3d(d+1)





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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3d(d+1





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