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1=1/5(10x-5)
We move all terms to the left:
1-(1/5(10x-5))=0
Domain of the equation: 5(10x-5))!=0We multiply all the terms by the denominator
x∈R
-(1+1*5(10x-5))=0
We calculate terms in parentheses: -(1+1*5(10x-5)), so:We add all the numbers together, and all the variables
1+1*5(10x-5)
determiningTheFunctionDomain 1*5(10x-5)+1
Wy multiply elements
5x(1+1
Back to the equation:
-(5x(1+1)
-(5x2=0
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