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1=1/5b-12
We move all terms to the left:
1-(1/5b-12)=0
Domain of the equation: 5b-12)!=0We get rid of parentheses
b∈R
-1/5b+12+1=0
We multiply all the terms by the denominator
12*5b+1*5b-1=0
Wy multiply elements
60b+5b-1=0
We add all the numbers together, and all the variables
65b-1=0
We move all terms containing b to the left, all other terms to the right
65b=1
b=1/65
b=1/65
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