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1=11x^2+10x
We move all terms to the left:
1-(11x^2+10x)=0
We get rid of parentheses
-11x^2-10x+1=0
a = -11; b = -10; c = +1;
Δ = b2-4ac
Δ = -102-4·(-11)·1
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-12}{2*-11}=\frac{-2}{-22} =1/11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+12}{2*-11}=\frac{22}{-22} =-1 $
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