1=128/322x+1

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Solution for 1=128/322x+1 equation: 



1=128/322x+1

We move all terms to the left:

1-(128/322x+1)=0



Domain of the equation: 322x+1)!=0

x∈R



We get rid of parentheses

-128/322x-1+1=0

We multiply all the terms by the denominator


-1*322x+1*322x-128=0

Wy multiply elements

-322x+322x-128=0

We add all the numbers together, and all the variables

-128!=0

There is no solution for this equation

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