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1=12x^2+11x
We move all terms to the left:
1-(12x^2+11x)=0
We get rid of parentheses
-12x^2-11x+1=0
a = -12; b = -11; c = +1;
Δ = b2-4ac
Δ = -112-4·(-12)·1
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-13}{2*-12}=\frac{-2}{-24} =1/12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+13}{2*-12}=\frac{24}{-24} =-1 $
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