1=16t2+50

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Solution for 1=16t2+50 equation: 



1=16t^2+50

We move all terms to the left:

1-(16t^2+50)=0

We get rid of parentheses

-16t^2-50+1=0

We add all the numbers together, and all the variables

-16t^2-49=0

a = -16; b = 0; c = -49;
Δ = b2-4ac
Δ = 02-4·(-16)·(-49)
Δ = -3136
Delta is less than zero, so there is no solution for the equation

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