1=2(1+2n)-4(n+5)

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Solution for 1=2(1+2n)-4(n+5) equation: 



1=2(1+2n)-4(n+5)

We move all terms to the left:

1-(2(1+2n)-4(n+5))=0

We add all the numbers together, and all the variables

-(2(2n+1)-4(n+5))+1=0



We calculate terms in parentheses: -(2(2n+1)-4(n+5)), so:

2(2n+1)-4(n+5)

We multiply parentheses

4n-4n+2-20

We add all the numbers together, and all the variables

-18

Back to the equation:

-(-18)



We add all the numbers together, and all the variables

19!=0

There is no solution for this equation

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