1=2(a+5)-2(-a-4)

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Solution for 1=2(a+5)-2(-a-4) equation: 



1=2(a+5)-2(-a-4)

We move all terms to the left:

1-(2(a+5)-2(-a-4))=0

We add all the numbers together, and all the variables

-(2(a+5)-2(-1a-4))+1=0



We calculate terms in parentheses: -(2(a+5)-2(-1a-4)), so:

2(a+5)-2(-1a-4)

We multiply parentheses

2a+2a+10+8

We add all the numbers together, and all the variables

4a+18

Back to the equation:

-(4a+18)



We get rid of parentheses

-4a-18+1=0

We add all the numbers together, and all the variables

-4a-17=0

We move all terms containing a to the left, all other terms to the right

-4a=17

a=17/-4

a=-4+1/4

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