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1=2(x-5)+3-x
We move all terms to the left:
1-(2(x-5)+3-x)=0
We calculate terms in parentheses: -(2(x-5)+3-x), so:We get rid of parentheses
2(x-5)+3-x
determiningTheFunctionDomain 2(x-5)-x+3
We add all the numbers together, and all the variables
-1x+2(x-5)+3
We multiply parentheses
-1x+2x-10+3
We add all the numbers together, and all the variables
x-7
Back to the equation:
-(x-7)
-x+7+1=0
We add all the numbers together, and all the variables
-1x+8=0
We move all terms containing x to the left, all other terms to the right
-x=-8
x=-8/-1
x=+8
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