1=2r+2(3/4r-1)=1/4r+6

Solution for 1=2r+2(3/4r-1)=1/4r+6 equation:

1=2r+2(3/4r-1)=1/4r+6

We move all terms to the left:

1-(2r+2(3/4r-1))=0


Domain of the equation: 4r-1))!=0

r∈R


We multiply all the terms by the denominator


-(2r+2(3+1*4r-1))=0


We calculate terms in parentheses: -(2r+2(3+1*4r-1)), so:

2r+2(3+1*4r-1)

We add all the numbers together, and all the variables

2r+2(1*4r+2)

We multiply parentheses

2r+8r+4

We add all the numbers together, and all the variables

10r+4

Back to the equation:

-(10r+4)


We get rid of parentheses

-10r-4=0

We move all terms containing r to the left, all other terms to the right

-10r=4

r=4/-10

r=-2/5