1=2r+2(3/4r-1)=1/4r+6

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Solution for 1=2r+2(3/4r-1)=1/4r+6 equation:



1=2r+2(3/4r-1)=1/4r+6
We move all terms to the left:
1-(2r+2(3/4r-1))=0
Domain of the equation: 4r-1))!=0
r∈R
We multiply all the terms by the denominator
-(2r+2(3+1*4r-1))=0
We calculate terms in parentheses: -(2r+2(3+1*4r-1)), so:
2r+2(3+1*4r-1)
We add all the numbers together, and all the variables
2r+2(1*4r+2)
We multiply parentheses
2r+8r+4
We add all the numbers together, and all the variables
10r+4
Back to the equation:
-(10r+4)
We get rid of parentheses
-10r-4=0
We move all terms containing r to the left, all other terms to the right
-10r=4
r=4/-10
r=-2/5

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