1=3(-2)+b

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Solution for 1=3(-2)+b equation: 



1=3(-2)+b

We move all terms to the left:

1-(3(-2)+b)=0



We calculate terms in parentheses: -(3(-2)+b), so:

3(-2)+b

determiningTheFunctionDomain
b+3(-2)

We add all the numbers together, and all the variables

b-6

Back to the equation:

-(b-6)



We get rid of parentheses

-b+6+1=0

We add all the numbers together, and all the variables

-1b+7=0

We move all terms containing b to the left, all other terms to the right

-b=-7

b=-7/-1

b=+7

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