1=3(k-6)-2

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Solution for 1=3(k-6)-2 equation: 



1=3(k-6)-2

We move all terms to the left:

1-(3(k-6)-2)=0



We calculate terms in parentheses: -(3(k-6)-2), so:

3(k-6)-2

We multiply parentheses

3k-18-2

We add all the numbers together, and all the variables

3k-20

Back to the equation:

-(3k-20)



We get rid of parentheses

-3k+20+1=0

We add all the numbers together, and all the variables

-3k+21=0

We move all terms containing k to the left, all other terms to the right

-3k=-21

k=-21/-3

k=+7

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