1=3(r-5)-2(r-4)

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Solution for 1=3(r-5)-2(r-4) equation:


Simplifying
1 = 3(r + -5) + -2(r + -4)

Reorder the terms:
1 = 3(-5 + r) + -2(r + -4)
1 = (-5 * 3 + r * 3) + -2(r + -4)
1 = (-15 + 3r) + -2(r + -4)

Reorder the terms:
1 = -15 + 3r + -2(-4 + r)
1 = -15 + 3r + (-4 * -2 + r * -2)
1 = -15 + 3r + (8 + -2r)

Reorder the terms:
1 = -15 + 8 + 3r + -2r

Combine like terms: -15 + 8 = -7
1 = -7 + 3r + -2r

Combine like terms: 3r + -2r = 1r
1 = -7 + 1r

Solving
1 = -7 + 1r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-1r' to each side of the equation.
1 + -1r = -7 + 1r + -1r

Combine like terms: 1r + -1r = 0
1 + -1r = -7 + 0
1 + -1r = -7

Add '-1' to each side of the equation.
1 + -1 + -1r = -7 + -1

Combine like terms: 1 + -1 = 0
0 + -1r = -7 + -1
-1r = -7 + -1

Combine like terms: -7 + -1 = -8
-1r = -8

Divide each side by '-1'.
r = 8

Simplifying
r = 8

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