1=3(u+4)+8u

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Solution for 1=3(u+4)+8u equation: 



1=3(u+4)+8u

We move all terms to the left:

1-(3(u+4)+8u)=0



We calculate terms in parentheses: -(3(u+4)+8u), so:

3(u+4)+8u

We add all the numbers together, and all the variables

8u+3(u+4)

We multiply parentheses

8u+3u+12

We add all the numbers together, and all the variables

11u+12

Back to the equation:

-(11u+12)



We get rid of parentheses

-11u-12+1=0

We add all the numbers together, and all the variables

-11u-11=0

We move all terms containing u to the left, all other terms to the right

-11u=11

u=11/-11

u=-1

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