1=3(x-2)+-2x

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Solution for 1=3(x-2)+-2x equation: 



1=3(x-2)+-2x

We move all terms to the left:

1-(3(x-2)+-2x)=0

We use the square of the difference formula

-(3(x-2)-2x)+1=0



We calculate terms in parentheses: -(3(x-2)-2x), so:

3(x-2)-2x

We add all the numbers together, and all the variables

-2x+3(x-2)

We multiply parentheses

-2x+3x-6

We add all the numbers together, and all the variables

x-6

Back to the equation:

-(x-6)



We get rid of parentheses

-x+6+1=0

We add all the numbers together, and all the variables

-1x+7=0

We move all terms containing x to the left, all other terms to the right

-x=-7

x=-7/-1

x=+7

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