1=3(x-2)+3-3x

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Solution for 1=3(x-2)+3-3x equation: 



1=3(x-2)+3-3x

We move all terms to the left:

1-(3(x-2)+3-3x)=0



We calculate terms in parentheses: -(3(x-2)+3-3x), so:

3(x-2)+3-3x

determiningTheFunctionDomain
3(x-2)-3x+3

We add all the numbers together, and all the variables

-3x+3(x-2)+3

We multiply parentheses

-3x+3x-6+3

We add all the numbers together, and all the variables

-3

Back to the equation:

-(-3)



We add all the numbers together, and all the variables

4!=0

There is no solution for this equation

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