1=3/2(-5)+b

Solution for 1=3/2(-5)+b equation:

1=3/2(-5)+b

We move all terms to the left:

1-(3/2(-5)+b)=0


Domain of the equation: 2(-5)+b)!=0

b∈R


We multiply all the terms by the denominator


-(3+1*2(-5)+b)=0


We calculate terms in parentheses: -(3+1*2(-5)+b), so:

3+1*2(-5)+b

determiningTheFunctionDomain
b+3+1*2(-5)

We add all the numbers together, and all the variables

b-7

Back to the equation:

-(b-7)


We get rid of parentheses

-b+7=0

We add all the numbers together, and all the variables

-1b+7=0

We move all terms containing b to the left, all other terms to the right

-b=-7

b=-7/-1

b=+7