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1=30t-t*t
We move all terms to the left:
1-(30t-t*t)=0
We add all the numbers together, and all the variables
-(+30t-t*t)+1=0
We get rid of parentheses
-30t+t*t+1=0
Wy multiply elements
t^2-30t+1=0
a = 1; b = -30; c = +1;
Δ = b2-4ac
Δ = -302-4·1·1
Δ = 896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{896}=\sqrt{64*14}=\sqrt{64}*\sqrt{14}=8\sqrt{14}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-8\sqrt{14}}{2*1}=\frac{30-8\sqrt{14}}{2} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+8\sqrt{14}}{2*1}=\frac{30+8\sqrt{14}}{2} $
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