1=3v+2(v-2)

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Solution for 1=3v+2(v-2) equation: 



1=3v+2(v-2)

We move all terms to the left:

1-(3v+2(v-2))=0



We calculate terms in parentheses: -(3v+2(v-2)), so:

3v+2(v-2)

We multiply parentheses

3v+2v-4

We add all the numbers together, and all the variables

5v-4

Back to the equation:

-(5v-4)



We get rid of parentheses

-5v+4+1=0

We add all the numbers together, and all the variables

-5v+5=0

We move all terms containing v to the left, all other terms to the right

-5v=-5

v=-5/-5

v=1

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