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1=3x-10/2x-3
We move all terms to the left:
1-(3x-10/2x-3)=0
Domain of the equation: 2x-3)!=0We get rid of parentheses
x∈R
-3x+10/2x+3+1=0
We multiply all the terms by the denominator
-3x*2x+3*2x+1*2x+10=0
Wy multiply elements
-6x^2+6x+2x+10=0
We add all the numbers together, and all the variables
-6x^2+8x+10=0
a = -6; b = 8; c = +10;
Δ = b2-4ac
Δ = 82-4·(-6)·10
Δ = 304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{304}=\sqrt{16*19}=\sqrt{16}*\sqrt{19}=4\sqrt{19}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{19}}{2*-6}=\frac{-8-4\sqrt{19}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{19}}{2*-6}=\frac{-8+4\sqrt{19}}{-12} $
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