1=3x-1604=x+20

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Solution for 1=3x-1604=x+20 equation: 



1=3x-160

We move all terms to the left:

1-(3x-160)=0

We get rid of parentheses

-3x+160+1=0

We add all the numbers together, and all the variables

-3x+161=0

We move all terms containing x to the left, all other terms to the right

-3x=-161

x=-161/-3

x=53+2/3

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