1=4a-(3-a)=17

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Solution for 1=4a-(3-a)=17 equation: 



1=4a-(3-a)=17

We move all terms to the left:

1-(4a-(3-a))=0

We add all the numbers together, and all the variables

-(4a-(-1a+3))+1=0



We calculate terms in parentheses: -(4a-(-1a+3)), so:

4a-(-1a+3)

We get rid of parentheses

4a+1a-3

We add all the numbers together, and all the variables

5a-3

Back to the equation:

-(5a-3)



We get rid of parentheses

-5a+3+1=0

We add all the numbers together, and all the variables

-5a+4=0

We move all terms containing a to the left, all other terms to the right

-5a=-4

a=-4/-5

a=4/5

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