1=6+3v+2v

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Solution for 1=6+3v+2v equation: 



1=6+3v+2v

We move all terms to the left:

1-(6+3v+2v)=0

We add all the numbers together, and all the variables

-(5v+6)+1=0

We get rid of parentheses

-5v-6+1=0

We add all the numbers together, and all the variables

-5v-5=0

We move all terms containing v to the left, all other terms to the right

-5v=5

v=5/-5

v=-1

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