1=6m+(2-m)

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Solution for 1=6m+(2-m) equation: 



1=6m+(2-m)

We move all terms to the left:

1-(6m+(2-m))=0

We add all the numbers together, and all the variables

-(6m+(-1m+2))+1=0



We calculate terms in parentheses: -(6m+(-1m+2)), so:

6m+(-1m+2)

We get rid of parentheses

6m-1m+2

We add all the numbers together, and all the variables

5m+2

Back to the equation:

-(5m+2)



We get rid of parentheses

-5m-2+1=0

We add all the numbers together, and all the variables

-5m-1=0

We move all terms containing m to the left, all other terms to the right

-5m=1

m=1/-5

m=-1/5

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