1=6x-5(3x+16)

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Solution for 1=6x-5(3x+16) equation: 



1=6x-5(3x+16)

We move all terms to the left:

1-(6x-5(3x+16))=0



We calculate terms in parentheses: -(6x-5(3x+16)), so:

6x-5(3x+16)

We multiply parentheses

6x-15x-80

We add all the numbers together, and all the variables

-9x-80

Back to the equation:

-(-9x-80)



We get rid of parentheses

9x+80+1=0

We add all the numbers together, and all the variables

9x+81=0

We move all terms containing x to the left, all other terms to the right

9x=-81

x=-81/9

x=-9

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