1=7(1+3q)

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Solution for 1=7(1+3q) equation: 



1=7(1+3q)

We move all terms to the left:

1-(7(1+3q))=0

We add all the numbers together, and all the variables

-(7(3q+1))+1=0



We calculate terms in parentheses: -(7(3q+1)), so:

7(3q+1)

We multiply parentheses

21q+7

Back to the equation:

-(21q+7)



We get rid of parentheses

-21q-7+1=0

We add all the numbers together, and all the variables

-21q-6=0

We move all terms containing q to the left, all other terms to the right

-21q=6

q=6/-21

q=-2/7

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