1=7(1-3b)=

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Solution for 1=7(1-3b)= equation:



1=7(1-3b)=
We move all terms to the left:
1-(7(1-3b))=0
We add all the numbers together, and all the variables
-(7(-3b+1))+1=0
We calculate terms in parentheses: -(7(-3b+1)), so:
7(-3b+1)
We multiply parentheses
-21b+7
Back to the equation:
-(-21b+7)
We get rid of parentheses
21b-7+1=0
We add all the numbers together, and all the variables
21b-6=0
We move all terms containing b to the left, all other terms to the right
21b=6
b=6/21
b=2/7

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