1=7(1-3b)=

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Solution for 1=7(1-3b)= equation: 



1=7(1-3b)=

We move all terms to the left:

1-(7(1-3b))=0

We add all the numbers together, and all the variables

-(7(-3b+1))+1=0



We calculate terms in parentheses: -(7(-3b+1)), so:

7(-3b+1)

We multiply parentheses

-21b+7

Back to the equation:

-(-21b+7)



We get rid of parentheses

21b-7+1=0

We add all the numbers together, and all the variables

21b-6=0

We move all terms containing b to the left, all other terms to the right

21b=6

b=6/21

b=2/7

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