1=7(v+4)+2v

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Solution for 1=7(v+4)+2v equation: 



1=7(v+4)+2v

We move all terms to the left:

1-(7(v+4)+2v)=0



We calculate terms in parentheses: -(7(v+4)+2v), so:

7(v+4)+2v

We add all the numbers together, and all the variables

2v+7(v+4)

We multiply parentheses

2v+7v+28

We add all the numbers together, and all the variables

9v+28

Back to the equation:

-(9v+28)



We get rid of parentheses

-9v-28+1=0

We add all the numbers together, and all the variables

-9v-27=0

We move all terms containing v to the left, all other terms to the right

-9v=27

v=27/-9

v=-3

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