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1=7x^2=x+2
We move all terms to the left:
1-(7x^2)=0
a = -7; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-7)·1
Δ = 28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{28}=\sqrt{4*7}=\sqrt{4}*\sqrt{7}=2\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{7}}{2*-7}=\frac{0-2\sqrt{7}}{-14} =-\frac{2\sqrt{7}}{-14} =-\frac{\sqrt{7}}{-7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{7}}{2*-7}=\frac{0+2\sqrt{7}}{-14} =\frac{2\sqrt{7}}{-14} =\frac{\sqrt{7}}{-7} $
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