1=r2+3

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Solution for 1=r2+3 equation: 



1=r2+3

We move all terms to the left:

1-(r2+3)=0

We add all the numbers together, and all the variables

-(+r^2+3)+1=0

We get rid of parentheses

-r^2-3+1=0

We add all the numbers together, and all the variables

-1r^2-2=0

a = -1; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·(-1)·(-2)
Δ = -8
Delta is less than zero, so there is no solution for the equation

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