1=z+48/9

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Solution for 1=z+48/9 equation: 



1=z+48/9

We move all terms to the left:

1-(z+48/9)=0

We add all the numbers together, and all the variables

-(+z+48/9)+1=0

We get rid of parentheses

-z+1-48/9=0

We multiply all the terms by the denominator


-z*9-48+1*9=0

We add all the numbers together, and all the variables

-z*9-39=0

Wy multiply elements

-9z-39=0

We move all terms containing z to the left, all other terms to the right

-9z=39

z=39/-9

z=-4+1/3

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