1A+2B+3C+4D=1

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Solution for 1A+2B+3C+4D=1 equation: 


Simplifying
1A + 2B + 3C + 4D = 1

Solving
1A + 2B + 3C + 4D = 1

Solving for variable 'A'.

Move all terms containing A to the left, all other terms to the right.

Add '-2B' to each side of the equation.
1A + 2B + 3C + -2B + 4D = 1 + -2B

Reorder the terms:
1A + 2B + -2B + 3C + 4D = 1 + -2B

Combine like terms: 2B + -2B = 0
1A + 0 + 3C + 4D = 1 + -2B
1A + 3C + 4D = 1 + -2B

Add '-3C' to each side of the equation.
1A + 3C + -3C + 4D = 1 + -2B + -3C

Combine like terms: 3C + -3C = 0
1A + 0 + 4D = 1 + -2B + -3C
1A + 4D = 1 + -2B + -3C

Add '-4D' to each side of the equation.
1A + 4D + -4D = 1 + -2B + -3C + -4D

Combine like terms: 4D + -4D = 0
1A + 0 = 1 + -2B + -3C + -4D
1A = 1 + -2B + -3C + -4D

Divide each side by '1'.
A = 1 + -2B + -3C + -4D

Simplifying
A = 1 + -2B + -3C + -4D

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