1a+2b+3c=56

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Solution for 1a+2b+3c=56 equation:


Simplifying
1a + 2b + 3c = 56

Solving
1a + 2b + 3c = 56

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-2b' to each side of the equation.
1a + 2b + -2b + 3c = 56 + -2b

Combine like terms: 2b + -2b = 0
1a + 0 + 3c = 56 + -2b
1a + 3c = 56 + -2b

Add '-3c' to each side of the equation.
1a + 3c + -3c = 56 + -2b + -3c

Combine like terms: 3c + -3c = 0
1a + 0 = 56 + -2b + -3c
1a = 56 + -2b + -3c

Divide each side by '1'.
a = 56 + -2b + -3c

Simplifying
a = 56 + -2b + -3c

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