1b+9(1b+1)=109

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Solution for 1b+9(1b+1)=109 equation: 



1b+9(1b+1)=109

We move all terms to the left:

1b+9(1b+1)-(109)=0

We add all the numbers together, and all the variables

1b+9(b+1)-109=0

We add all the numbers together, and all the variables

b+9(b+1)-109=0

We multiply parentheses

b+9b+9-109=0

We add all the numbers together, and all the variables

10b-100=0

We move all terms containing b to the left, all other terms to the right

10b=100

b=100/10

b=10

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