1c(1c+3)-1c(c-4)=9c-16

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Solution for 1c(1c+3)-1c(c-4)=9c-16 equation: 


Simplifying
1c(1c + 3) + -1c(c + -4) = 9c + -16

Reorder the terms:
1c(3 + 1c) + -1c(c + -4) = 9c + -16
(3 * 1c + 1c * 1c) + -1c(c + -4) = 9c + -16
(3c + 1c2) + -1c(c + -4) = 9c + -16

Reorder the terms:
3c + 1c2 + -1c(-4 + c) = 9c + -16
3c + 1c2 + (-4 * -1c + c * -1c) = 9c + -16
3c + 1c2 + (4c + -1c2) = 9c + -16

Reorder the terms:
3c + 4c + 1c2 + -1c2 = 9c + -16

Combine like terms: 3c + 4c = 7c
7c + 1c2 + -1c2 = 9c + -16

Combine like terms: 1c2 + -1c2 = 0
7c + 0 = 9c + -16
7c = 9c + -16

Reorder the terms:
7c = -16 + 9c

Solving
7c = -16 + 9c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-9c' to each side of the equation.
7c + -9c = -16 + 9c + -9c

Combine like terms: 7c + -9c = -2c
-2c = -16 + 9c + -9c

Combine like terms: 9c + -9c = 0
-2c = -16 + 0
-2c = -16

Divide each side by '-2'.
c = 8

Simplifying
c = 8

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