1d+(1d*4-12)=(1d*3)

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Solution for 1d+(1d*4-12)=(1d*3) equation:


Simplifying
1d + (1d * 4 + -12) = (1d * 3)

Reorder the terms for easier multiplication:
1d + (1 * 4d + -12) = (1d * 3)

Multiply 1 * 4
1d + (4d + -12) = (1d * 3)

Reorder the terms:
1d + (-12 + 4d) = (1d * 3)

Remove parenthesis around (-12 + 4d)
1d + -12 + 4d = (1d * 3)

Reorder the terms:
-12 + 1d + 4d = (1d * 3)

Combine like terms: 1d + 4d = 5d
-12 + 5d = (1d * 3)

Reorder the terms for easier multiplication:
-12 + 5d = (1 * 3d)

Multiply 1 * 3
-12 + 5d = (3d)

Solving
-12 + 5d = (3d)

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '(-3d)' to each side of the equation.
-12 + 5d + (-3d) = (3d) + (-3d)

Combine like terms: 5d + (-3d) = 2d
-12 + 2d = (3d) + (-3d)

Combine like terms: (3d) + (-3d) = 0
-12 + 2d = 0

Add '12' to each side of the equation.
-12 + 12 + 2d = 0 + 12

Combine like terms: -12 + 12 = 0
0 + 2d = 0 + 12
2d = 0 + 12

Combine like terms: 0 + 12 = 12
2d = 12

Divide each side by '2'.
d = 6

Simplifying
d = 6

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