1f+12=3f-20

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Solution for 1f+12=3f-20 equation: 



1f+12=3f-20

We move all terms to the left:

1f+12-(3f-20)=0

We add all the numbers together, and all the variables

f-(3f-20)+12=0

We get rid of parentheses

f-3f+20+12=0

We add all the numbers together, and all the variables

-2f+32=0

We move all terms containing f to the left, all other terms to the right

-2f=-32

f=-32/-2

f=+16

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