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1h/2h+1/3(h-6)=5h/6h+2
We move all terms to the left:
1h/2h+1/3(h-6)-(5h/6h+2)=0
Domain of the equation: 2h!=0
h!=0/2
h!=0
h∈R
Domain of the equation: 3(h-6)!=0
h∈R
Domain of the equation: 6h+2)!=0We get rid of parentheses
h∈R
1h/2h+1/3(h-6)-5h/6h-2=0
We calculate fractions
We do not support ehpression: h^3(h
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