1k+(k+1)+(k+2)=4k

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Solution for 1k+(k+1)+(k+2)=4k equation: 



1k+(k+1)+(k+2)=4k

We move all terms to the left:

1k+(k+1)+(k+2)-(4k)=0

We add all the numbers together, and all the variables

-3k+(k+1)+(k+2)=0

We get rid of parentheses

-3k+k+k+1+2=0

We add all the numbers together, and all the variables

-1k+3=0

We move all terms containing k to the left, all other terms to the right

-k=-3

k=-3/-1

k=+3

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