1m-2m-5m2=0

Solution for 1m-2m-5m2=0 equation:

1m-2m-5m^2=0

We add all the numbers together, and all the variables

-5m^2-1m=0

a = -5; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-5)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-5}=\frac{0}{-10}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-5}=\frac{2}{-10}
=-1/5
$