1n-6(n-1)=7(1n+6)+6n

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Solution for 1n-6(n-1)=7(1n+6)+6n equation: 



1n-6(n-1)=7(1n+6)+6n

We move all terms to the left:

1n-6(n-1)-(7(1n+6)+6n)=0

We add all the numbers together, and all the variables

1n-6(n-1)-(7(n+6)+6n)=0

We add all the numbers together, and all the variables

n-6(n-1)-(7(n+6)+6n)=0

We multiply parentheses

n-6n-(7(n+6)+6n)+6=0



We calculate terms in parentheses: -(7(n+6)+6n), so:

7(n+6)+6n

We add all the numbers together, and all the variables

6n+7(n+6)

We multiply parentheses

6n+7n+42

We add all the numbers together, and all the variables

13n+42

Back to the equation:

-(13n+42)



We add all the numbers together, and all the variables

-5n-(13n+42)+6=0

We get rid of parentheses

-5n-13n-42+6=0

We add all the numbers together, and all the variables

-18n-36=0

We move all terms containing n to the left, all other terms to the right

-18n=36

n=36/-18

n=-2

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