1p+1(1-p)=0p+2(1-p)=2p+0(1-p)

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Solution for 1p+1(1-p)=0p+2(1-p)=2p+0(1-p) equation: 



1p+1(1-p)=0p+2(1-p)=2p+0(1-p)

We move all terms to the left:

1p+1(1-p)-(0p+2(1-p))=0

We add all the numbers together, and all the variables

1p+1(-1p+1)-(0p+2(-1p+1))=0

We add all the numbers together, and all the variables

p+1(-1p+1)-(0p+2(-1p+1))=0



We calculate terms in parentheses: -(0p+2(-1p+1)), so:

0p+2(-1p+1)

We add all the numbers together, and all the variables

p+2(-1p+1)

We multiply parentheses

p-2p+2

We add all the numbers together, and all the variables

-1p+2

Back to the equation:

-(-1p+2)



We get rid of parentheses

p+1(-1p+1)+1p-2=0

We add all the numbers together, and all the variables

2p+1(-1p+1)-2=0

We move all terms containing p to the left, all other terms to the right

2p+1(-1p+1)=2

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