1p+3(1-p)=3p+2(1-p)

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Solution for 1p+3(1-p)=3p+2(1-p) equation: 



1p+3(1-p)=3p+2(1-p)

We move all terms to the left:

1p+3(1-p)-(3p+2(1-p))=0

We add all the numbers together, and all the variables

1p+3(-1p+1)-(3p+2(-1p+1))=0

We add all the numbers together, and all the variables

p+3(-1p+1)-(3p+2(-1p+1))=0

We multiply parentheses

p-3p-(3p+2(-1p+1))+3=0



We calculate terms in parentheses: -(3p+2(-1p+1)), so:

3p+2(-1p+1)

We multiply parentheses

3p-2p+2

We add all the numbers together, and all the variables

p+2

Back to the equation:

-(p+2)



We add all the numbers together, and all the variables

-2p-(p+2)+3=0

We get rid of parentheses

-2p-p-2+3=0

We add all the numbers together, and all the variables

-3p+1=0

We move all terms containing p to the left, all other terms to the right

-3p=-1

p=-1/-3

p=1/3

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