1q+2=6q-(-2)+8q+4

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Solution for 1q+2=6q-(-2)+8q+4 equation: 



1q+2=6q-(-2)+8q+4

We move all terms to the left:

1q+2-(6q-(-2)+8q+4)=0

We add all the numbers together, and all the variables

q-(6q-(-2)+8q+4)+2=0



We calculate terms in parentheses: -(6q-(-2)+8q+4), so:

6q-(-2)+8q+4

determiningTheFunctionDomain
6q+8q+4-(-2)

We add all the numbers together, and all the variables

14q+6

Back to the equation:

-(14q+6)



We get rid of parentheses

q-14q-6+2=0

We add all the numbers together, and all the variables

-13q-4=0

We move all terms containing q to the left, all other terms to the right

-13q=4

q=4/-13

q=-4/13

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