1q+4(1-q)=3q+2(1-q)

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Solution for 1q+4(1-q)=3q+2(1-q) equation: 



1q+4(1-q)=3q+2(1-q)

We move all terms to the left:

1q+4(1-q)-(3q+2(1-q))=0

We add all the numbers together, and all the variables

1q+4(-1q+1)-(3q+2(-1q+1))=0

We add all the numbers together, and all the variables

q+4(-1q+1)-(3q+2(-1q+1))=0

We multiply parentheses

q-4q-(3q+2(-1q+1))+4=0



We calculate terms in parentheses: -(3q+2(-1q+1)), so:

3q+2(-1q+1)

We multiply parentheses

3q-2q+2

We add all the numbers together, and all the variables

q+2

Back to the equation:

-(q+2)



We add all the numbers together, and all the variables

-3q-(q+2)+4=0

We get rid of parentheses

-3q-q-2+4=0

We add all the numbers together, and all the variables

-4q+2=0

We move all terms containing q to the left, all other terms to the right

-4q=-2

q=-2/-4

q=1/2

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