1r(r)+12=1r+6+1r(r)-2r

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Solution for 1r(r)+12=1r+6+1r(r)-2r equation: 



1r(r)+12=1r+6+1r(r)-2r

We move all terms to the left:

1r(r)+12-(1r+6+1r(r)-2r)=0

We add all the numbers together, and all the variables

1rr-(-1r+1rr+6)+12=0

We get rid of parentheses

1rr+1r-1rr-6+12=0

We add all the numbers together, and all the variables

r+1rr-1rr+6=0

We move all terms containing r to the left, all other terms to the right

r+1rr-1rr=-6

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