1t(t+1)=2t

Solution for 1t(t+1)=2t equation:

1t(t+1)=2t

We move all terms to the left:

1t(t+1)-(2t)=0

We add all the numbers together, and all the variables

-2t+1t(t+1)=0

We multiply parentheses

t^2-2t+t=0

We add all the numbers together, and all the variables

t^2-1t=0

a = 1; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·1·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*1}=\frac{0}{2}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*1}=\frac{2}{2}
=1
$