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1v+-9/10v+6=11
We move all terms to the left:
1v+-9/10v+6-(11)=0
Domain of the equation: 10v!=0determiningTheFunctionDomain 1v-9/10v+6-11+=0
v!=0/10
v!=0
v∈R
We add all the numbers together, and all the variables
v-9/10v=0
We multiply all the terms by the denominator
v*10v-9=0
Wy multiply elements
10v^2-9=0
a = 10; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·10·(-9)
Δ = 360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{360}=\sqrt{36*10}=\sqrt{36}*\sqrt{10}=6\sqrt{10}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{10}}{2*10}=\frac{0-6\sqrt{10}}{20} =-\frac{6\sqrt{10}}{20} =-\frac{3\sqrt{10}}{10} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{10}}{2*10}=\frac{0+6\sqrt{10}}{20} =\frac{6\sqrt{10}}{20} =\frac{3\sqrt{10}}{10} $
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